econfly
Member
Nice Rob! Never heard the 3.5 factor in that equation.
I learn something from you almost daily!
Thanks! I just made that up. If the battery mAh is about equal to the current demand divided by 3.5 then the flight time is 60 / 3.5 = about 17+ minutes. Knock off a bit for not fully depleting the battery and you end up around 15 minutes flight time. This is 3.5C current demand, so just about any C rated battery is going to be fine assuming we could trust C ratings. As it is, 15C or above is plenty for AP work.
15-20 minutes seems to always be about the ideal spot for a design. Divide by 3 for closer to 20 minutes.
